X^2+9x+20=(x+4)(x+5)

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Solution for X^2+9x+20=(x+4)(x+5) equation: 



X^2+9X+20=(X+4)(X+5)

We move all terms to the left:

X^2+9X+20-((X+4)(X+5))=0

We multiply parentheses ..

X^2-((+X^2+5X+4X+20))+9X+20=0



We calculate terms in parentheses: -((+X^2+5X+4X+20)), so:

(+X^2+5X+4X+20)

We get rid of parentheses

X^2+5X+4X+20

We add all the numbers together, and all the variables

X^2+9X+20

Back to the equation:

-(X^2+9X+20)



We add all the numbers together, and all the variables

X^2+9X-(X^2+9X+20)+20=0

We get rid of parentheses

X^2-X^2+9X-9X-20+20=0

We add all the numbers together, and all the variables

=0

X=0/1

X=0

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